2236. 判断根结点是否等于子结点之和
为保证权益,题目请参考 2236. 判断根结点是否等于子结点之和(From LeetCode).
解决方案1
CPP
C++
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
struct TreeNode {
int val;
TreeNode* left;
TreeNode* right;
TreeNode() : val(0), left(nullptr), right(nullptr) {}
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
TreeNode(int x, TreeNode* left, TreeNode* right) : val(x), left(left), right(right) {}
};
class Solution {
public:
bool checkTree(TreeNode* root) {
return root->val == (root->left->val + root->right->val);
}
};
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
Python
python
# 2236. 判断根结点是否等于子结点之和
# https://leetcode.cn/problems/root-equals-sum-of-children/
from typing import Optional
# Definition for a binary tree node.
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def checkTree(self, root: Optional[TreeNode]) -> bool:
return root.val == root.left.val + root.right.val
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18